Suppose that we are dealing with four genes each gene consis
Suppose that we are dealing with four genes, each gene consisting of a dominant allele (capital letter) and a recessive allele (small case letter). If the cross CcMmLlPP X CCmmLlpp is made, what is the probability of obtaining an individual who is CcmmLLPp?
1/2 or 1/4 or 1/8 or 1/16 or 1/32
Solution
Answer: 1/16
Explanation:
CcMmLlPP gives 8 gametes
CCmmLlpp gives 2 gametes
8 x 2 = 16 different genotypes will produce from the cross. Among them one will be CcmmLLPp i.e., 1/16.
