What is the solution of the system 5x 6y 20 9x 11 v 32So
Solution
we have
5x + 6y = 20 (1)
9x + 11y = 32 (2)
we have to make the coefficient of any one variable( \"x\" or \"y\") same.
lets make coefficient of \"x\" term same in both the equations
in order to make coefficient of \"x\" same we multiply eq (1) by \"9\" and eq (2) by \"5\" .
eq (1) X 9
45x +54y =180 (3)
eq (2) X 5
45x +55y =160 (4)
now we subtract eq (3) from (4) so that we can remove the variable \"x\"
45x +54y =180
45x +55y =160
- - - we get
-y = 20
multiply both sides by \"-1\"
y = -20
now subtituite the value \"y\" = -20 in any equation above (\"1\" , \"2\" , \"3\" ,\"4\")
subtituiting y = -20 in \"1\" we get
5x + 6*(-20) = 20
5x - 120 = 20 (if a postive number is multiplied by a negative number the result is negative eg: 2 * (-2) = -6 )
5x = 140
x = 28
we write coordinates as (x,y)
so the answer is (28 , -20)
