A tourist bureau survey showed that 75 of those who seek inf
A tourist bureau survey showed that 75% of those who seek information about the state actually come to visit. The office received 8 requests for information. Find:
a) the probability that more than five of the people will visit
b) the probability that at least 2 of the people will NOT visit
c) the probability that less than 4 of the people will visit
d) the probability that 4-6, inclusive, of the people will visit
e) what is the expected number of visitors from this group
Solution
a)
Note that P(more than x) = 1 - P(at most x).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 8
p = the probability of a success = 0.75
x = our critical value of successes = 5
Then the cumulative probability of P(at most x) from a table/technology is
P(at most 5 ) = 0.321456909
Thus, the probability of at least 6 successes is
P(more than 5 ) = 0.678543091 [ANSWER]
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b)
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 8
p = the probability of a success = 0.25
x = our critical value of successes = 2
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 1 ) = 0.367080688
Thus, the probability of at least 2 successes is
P(at least 2 ) = 0.632919312 [ANSWER]
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c)
Note that P(fewer than x) = P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 8
p = the probability of a success = 0.75
x = our critical value of successes = 4
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 3 ) = 0.027297974
Which is also
P(fewer than 4 ) = 0.027297974 [ANSWER]
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d)
Note that P(between x1 and x2) = P(at most x2) - P(at most x1 - 1)
Here,
x1 = 4
x2 = 6
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 8
p = the probability of a success = 0.75
Then
P(at most 3 ) = 0.027297974
P(at most 6 ) = 0.632919312
Thus,
P(between x1 and x2) = 0.605621338 [ANSWER]
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e)
E(x) = n p = 8*0.75 = 6 [ANSWER]

