The probability that a bearing meets a specification is 0 91

The probability that a bearing meets a specification is 0. 91. Nine bearings are picked at random. Calculate the probability that all nine meet the specification more than seven meet the specification one or none meets the specification exactly seven meet the specification. P (all nine meet the specification) = |0. 428| (Round to four decimal places as needed. ) P (more than seven meet the specification) = |0. 4491| (Round to four decimal places as needed. ) P (one or none meets the specification) = |0. 572l| (Round to four decimal places as needed. Use scientific notation. Use the multiplication symbol in the math palette as needed. ) P (exactly seven meet the specification) = |0. 5768| (Round to four decimal places as needed. )

Solution

here X~bin(9,0.91).

a) P(X=9)= (0.91)⁹ = .428

b) P(X>6)=.959522

c) P(X<2)= it has 0 probability

d)  P(X=7)=0.150688