Using the simple random sample of weights of women from a da

Using the simple random sample of weights of women from a data set, we obtain these sample statistics:

n equals 40 and x over bar equals144.56lb. Research from other sources suggests that the population of weights of women has a standard deviation given by sigma equals 32.84 lb.

a. Find the best point estimate of the mean weight of all women.

b. Find a 99%

confidence interval estimate of the mean weight of all women.Click here to view a t distribution table.

Click here to view page 1 of the standard normal distribution table.

Click here to view page 2 of the standard normal distribution table.

a. The best point estimate is

lb.

(Type an integer or a decimal.)

a)
Point of estimate(x)=144.56
b)
CI = x ± t a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
ta/2 = t-table value
CI = Confidence Interval

Standard deviation( sd )=32.84
Sample Size(n)=40
Confidence Interval = [ 144.56 ± t a/2 ( 32.84/ Sqrt ( 40) ) ]
= [ 144.56 - 2.708 * (5.192) , 144.56 + 2.708 * (5.192) ]
= [ 130.499,158.621 ]

Using the simple random sample of weights of women from a data set, we obtain these sample statistics: n equals 40 and x over bar equals144.56lb. Research from

Using the simple random sample of weights of women from a da

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