A basketball player can make 7 out of 10 free throws on aver
A basketball player can make 7 out of 10 free throws on average. Calculate the following probabilities that the basketball player will the first two shots and make the last two out of 4?
Solution
Binomial Distribution
PMF of B.D is = f ( k ) = ( n k ) p^k * ( 1- p) ^ n-k
Where
k = number of successes in trials
n = is the number of independent trials
p = probability of success on each trial
P( X = 5 ) = ( 6 5 ) * ( 0.3^5) * ( 1 - 0.3 )^1
= 0.0102
