A population of bacteria is growing according to the equatio

A population of bacteria is growing according to the equation P(t) = 1700e^0.04t. Estimate when the population will exceed 1886. t= Preview Give your answer accurate to one decimal place.

Solution

P(t) = 1700 e^.04t

lets plug P(t) = 1886

1886 = 1700 e^.04t

dividing both sides by 1700

1886/1700 = e^.04t

1.1094 = e^.04t

t = ln (1.1094) / .04

t = 2.6

 A population of bacteria is growing according to the equation P(t) = 1700e^0.04t. Estimate when the population will exceed 1886. t= Preview Give your answer ac

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