Verify the identify Cos2 x sin2 x1 tan2 x cos2 x To verif

Verify the identify. Cos^2 x - sin^2 x/1 - tan^2 x = cos^2 x To verify the identify, start with the more complicated side and transform it to look like to other side. Choose the correct transformations and transform the expression at each step cos^2 x - sinb^2 x/1 - tan^2 x = cos^2 x - sin^2 x/1 - = cos^2 x - sin^2 x/= (cos^2 x - sin^2 x) + Rewrite the main fraction bar as + = cos^2 x - sin^2 x). Invert the divisor and multiply. = cos^2 x

Solution

(cos²x - sin²x)/(1-tan²x)= cos²x

(Cos²x-sin²x)/(1-tan²x)

tan²x= sin²x/cos²x

Plugging sin²x/cos²x for tan²x we get

(cos²x-sin²x)/(1-sin²x/cos²x)

So in the first fill in the blanks we have to write sin²x/cos²x

(cos²x-sin²x)/((co²x-sin²x)/cos²x)

In the second fill in the blanks, we have to write (cos²x-sin²x)/cos²x

(cos²x-sin²x )divided by (cos²x-sin²x)/cos² x

In the third fill in the blanks,we have to write (cos²x-sin²x)/cos²x

(cos²x-sin²x)*cos²x/(cos²x-sin²x)

In the next fill in the blanks,we have to write cos²2x/(cos²x-sin²x)

cos²2x