In the gear system shown gear 1 is located on the motor shaf

In the gear system shown, gear 1 is located on the motor shaft and turns 1, 200 rpm. Find the speed at which the load is being raised.

N1 = 32, N2 = 84, N3 = 96

W3 = W1*N1/N3 = 1200*32/96 = 400 RPM

W2 = W1N1/N2 = 1200*32/84 = 3200/7 RPM

Net movement of load = W3R3 -W2R2 = (400*25\"/2) - (3200/7 *21/2) = 200\" per min