Homework SoursePlease be sure to write in C language Programmers for a Bett
Please be sure to write in C language
Programmers for a Better Tomorrow is now in partnership with a local Food Bank which distributes food items to people in need. People come in to a Food Bank and make their donations, and others might come in to make a request for any food item they want.
A Food Bank Management Program is used to keep track of the stock the Food Bank has (i.e., the donations), keep a record of requests that come in, fulfilling requests and printing the status report which consists of the amount of stock present in the food bank and the requests that are not yet fulfilled.
The program will require you to make at least one array. You may choose to make multiple onedimensional arrays: one to serve as a Donations Table and one to serve as a Request Table. The index of the array will represent the inventory type. The value in the array will represent the amount present or needed of that type.
You may, instead, choose to combine these to two arrays into a single two-dimensional array.
There are 5 inventory types: 0. Protein 1. Dairy 2. Grains 3. Vegetables 4. Fruits
Your program should allow the user the following options: 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit
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Option 1: Ask the user for the inventory type and amount of the donation to be made. When the donation has been added to the donations table, the program should notify the user by printing out “Donation Added”.
Option 2: Ask the user for the inventory type and amount of the request to be made. When the request has been added to the requests table, the program should notify the user by printing out “Request Added”.
Option 3: Check each type of inventory in the Request Table.
For each item that has a value in the request table, check to see if there is inventory of the same type in the donations table.
If there are no donations of that type, print “<type x> requests cannot be fulfilled.” Replace <type x> with the correct inventory type (Dairy, Fruit, etc.).
If there is some inventory in the donations table, but not enough to process all requests, print “<type x> requests will be partially fulfilled”. Reduce both the donation and request amounts based on how much of the request was able to be fulfilled. Replace< type x> with the correct inventory type (Dairy, Fruit, etc.).
If there is enough inventory to fulfill the request, print “type x> requests will be fulfilled.” Reduce the appropriate amount from the Donations Table and remove the amount from the Request Table. Replace <type x> with the correct inventory type (Dairy, Fruit, etc.).
Option 4: Print both tables, indicating which is for donations and which is for requests. After options 1, 2, 3, and 4 prompt the user with the menu again.
Option 5: Print “Thank you for running our system!” and then the program exits.
Do not prompt the user for any more information.
Sample Data Items You may wish to use these data structures to help you solve the problem.
int status[2][5]; char TYPES[5][20] = {“PROTEIN”, “DAIRY”, “GRAINS”, “VEGETABLES”, “FRUITS”};
The values in “TYPES” are strings and may be printed with %s. For example, to print “DAIRY” we could use printf(“%s”, TYPES[1]);
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Input Specification 1. All inputs will be greater than or equal to zero
Output Specification View the sample run to see how the output tables should be formatted.
Output Sample Below is a sample output of running the program. Note that this sample is NOT a comprehensive test. You should test your program with different data than is shown here based on the specifications given above.
In the sample run below, for clarity and ease of reading, the user input is given in italics while the program output is in bold. (Note: When you actually run your program no bold or italics should appear at all. These are simply used in this description for clarity’s sake.)
Sample Run Welcome to the Food Bank Management Program! What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 1
What donation type would you like to enter? 0. Protein 1. Dairy 2. Grains 3. Vegetables 4. Fruits 0
How many would you like to enter? 5 Donation Added.
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 1
What donation type would you like to enter? 0. Protein 1. Dairy
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2. Grains 3. Vegetables 4. Fruits 2
How many would you like to enter? 10 Donation Added.
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 1
What donation type would you like to enter? 0. Protein 1. Dairy 2. Grains 3. Vegetables 4. Fruits 4
How many would you like to enter? 7 Donation Added.
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 4 Protein: Donations: 5 Requests: 0 Dairy: Donations: 0 Requests:
0 Grains: Donations: 10 Requests: 0 Vegetables: Donations: 0 Requests: 0 Fruits: Donations: 7 Requests: 0
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 1
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What donation type would you like to enter? 0. Protein 1. Dairy 2. Grains 3. Vegetables 4. Fruits 0
How many would you like to enter? 3 Donation Added.
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 2
What would you like to request? 0. Protein 1. Dairy 2. Grains 3. Vegetables 4. Fruits 1
How many would you like to request? 5 Request Added.
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 2
What would you like to request? 0. Protein 1. Dairy 2. Grains 3. Vegetables 4. Fruits 2
How many would you like to request? 15 Request Added.
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What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 4 Protein: Donations: 8 Requests: 0 Dairy: Donations: 0 Requests:
5 Grains: Donations: 10 Requests: 15 Vegetables: Donations: 0 Requests: 0 Fruits: Donations: 7 Requests: 0
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 3
Dairy requests cannot be fulfilled. Grain requests will be partially fulfilled.
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 4 Protein: Donations: 8 Requests: 0 Dairy: Donations: 0 Requests:
5 Grains: Donations: 0 Requests: 5 Vegetables: Donations: 0 Requests: 0 Fruits: Donations: 7 Requests: 0
What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 6
Sorry, that was not a valid input.
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What would you like to do? 1. Enter a Donation 2. Enter a Request 3. Fulfill Requests 4. Print status report 5. Exit 5 Thank you for running our system!
Restrictions Although you may use other compilers, your program must compile and run using Code::Blocks.
Solution
#include <stdio.h>
int main() {
int choice, i, number, type;
int temp_donations[5] = {0};
int donations[5] = {0};
int request[5] = {0};
int temp;
char TYPES[5][20] = {\"Protein\", \"Dairy\", \"Grains\", \"Vegetables\", \"Fruits\"};
printf(\"Welcome to the Food Bank Management Program!\ \");
//Give and ask for the user\'s choice
printf(\"What would you like to do?\ \");
printf(\"\\t1. Enter a Donation\ \");
printf(\"\\t2. Enter a Request\ \");
printf(\"\\t3. Fulfill Request\ \");
printf(\"\\t4. Print status report\ \");
printf(\"\\t5. Exit\ \");
scanf(\"%d\", &choice);
printf(\"\ \");
//Print if choice is greater than 5 or less than 1
if(choice > 5 || choice < 1)
printf(\"Sorry, that was not a valid input.\ \ \");
while (choice != 5) {
switch (choice) {
case 1:
//ask user the type of food they would like to donate
printf(\"\ What donation type would you like to enter?\ \");
number = 0;
for(i=0; i<5; i++){
printf(\"\\t%d. %s\ \",number, TYPES[i]);
number += 1;
}
//user input for food type and amount to donate
scanf(\"%d\", &type);
printf(\"\ How many would you like to enter? \");
scanf(\"%d\", &temp); // you need to add it to existing requests, not replace the existing requests
donations[type] += temp;
printf(\"Donation Added.\ \ \");
break;
case 2:
//ask user the type of food they would like to request
printf(\"\ What would you like to request?\ \");
number = 0;
for(i=0; i<5; i++){
printf(\"\\t%d. %s\ \",number, TYPES[i]);
number += 1;
}
//user input for request and amount requested
scanf(\"%d\", &type);
printf(\"\ How many would you like to request? \");
scanf(\"%d\", &temp); // you need to add it to existing requests, not replace the existing requests
request[type] += temp;
printf(\"Request Added!\ \ \");
break;
case 3:
//go through foods and fulfill the requests if possible
for(i=0; i<5; i++){
if (request[i] > donations[i] && donations[i] == 0)
printf(\"%s requests cannot be fulfilled.\ \", TYPES[i]);
else if (request[i] > donations[i]){
printf(\"%s requests will be partially fulfilled.\ \", TYPES[i]);
temp_donations[i] = donations[i];
donations[i] -= donations[i];
request[i] -= temp_donations[i];
}
else {
donations[i] -= request[i];
request[i] -= request[i];
}
}
printf(\"\ \");
break;
case 4:
//print table of current donations and requests
for(i=0; i<5; i++){
printf(\"\\t%-10s: Donations: %-2d Requests: %-2d\ \", TYPES[i], donations[i], request[i]);
}
printf(\"\ \");
break;
}
//reask for user\'s choice
printf(\"What would you like to do?\ \");
printf(\"\\t1. Enter a Donation\ \");
printf(\"\\t2. Enter a Request\ \");
printf(\"\\t3. Fulfill Request\ \");
printf(\"\\t4. Print status report\ \");
printf(\"\\t5. Exit\ \");
scanf(\"%d\", &choice);
printf(\"\ \");
if(choice > 5 || choice < 1)
printf(\"Sorry, that was not a valid input.\ \ \");
}
printf(\"Thank you for running our system!\ \");
return 0;
}
