A square current loop 52 cm on each side carries a 470 mA cu

A square current loop 5.2 cm on each side carries a 470 mA current. The loop is in a 0.60 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30 away from the field direction.What is the magnitude of the torque on the current loop

Solution

Torque acting on the loop is,

tow = N * I *A * B *sin 30

tow = 1* 0.47 *5.2*5.2*10^-4 * 0.6 *sin 30

tow = 0.0003812 =  0.38*10 ^-3 N.m

tow = 1.4 *10 ^-3 N.m