Solve sin2 x cos2 x 1Solutionin a rightr angled triangle w

Solution

in a rightr angled triangle we have

sin(x) = Perpandicular/hypotenuse = P/H

cos(x) = Base/hypotenuse = B/H

sin²(x) + cos²(x) = (P/H)² + (B/H)² = (P² + B²)/H²

using pythagoras theorem, P² + B² = H²

=> sin²(x) + cos²(x) = H²/H²

=> sin²(x) + cos²(x) = 1 (proved)

sin(x) = Perpandicular/hypotenuse = P/H