The muzzle velocity of a gun is 30 x 103 cms A man shoots on

The muzzle velocity of a gun is 3.0 x 10^3 cm/s. A man shoots one shot each second straight up into the air, which is considered frictionless. How many bullets will be in the air at any time?

Solution

maximum height reached by the bullets:

    h = v^2/2g = [3x10^3*10^-2 ]² / 2*9.8 =45.91 m

time taken by the bullets to reach maximum height:

    t = sqrt[2h/g] = 3.06 s

since each bullet fired from the gun per each second and tiem is 3.0 6s, so the total bullets in the air are 3.