Using the Mesh Equation Technique and Cramers Rule find the
Using the Mesh Equation Technique and Cramer\'s Rule, find the current, IL, for the circuit given in Figure #2. Label all clockwise currents on the schematic.
Solution
consider left side current as i1
consider right side loop current as i2
apply kvl to left side loop
-60+10i1+10(i1-i2)+30=0
2i1-i2=3
apply kvl to right side loop
20i2+30i2-30+10(i2-i1)=0
-i1+6i2=3
from the above equations
i1=1.909 amps
i2=0.818 amps
current through left side 10 ohms resistor=i1=1.909 amps
current through middle 10 ohms resistor=(i1-i2)=1.091 amps
current through 20 ohms and 30 ohms resistors=i2=0.818 amps
