Please show work Thank you In the circuit of the figure belo

Please show work! Thank you!

In the circuit of the figure below, the switch S has been open for a long time. It is then suddenly closed. Take epsilon = 10.0 V, = T_1=59.0 kOmega, R_2= 115 kOmega, and C = 14.0 MewF Determine the time constant before the switch is closed. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully, s Determine the time constant after the switch is closed. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully, s Let the switch be closed at t = 0. Determine the current in the switch as a function of time. (Assume I is in A and t is in s. Do not enter units in your expression. Use the following as necessary: t.)

Solution

T_open = R C = (59 + 115) * 10³ * 14.0 * 10^-6

= 2.44 s

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When the switch is closed, the capacitor discharges through 115 kohm resistor

Tclosed = 115 * 10³ * 14.0 * 10^-6 = 1.61 s

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I = I_b + I_c = [ delta V_b / R ] + [I₀ e^-t/T_closed]

= [ 10 / 59 * 10³ ] + [I₀ e^-t/1.61]

I₀ = 10 / 115 * 10³ = 86.9 muA

I = [ 10 / 59 * 10³ ] + 86.9 e^-t/1.61 muA