How fast do you have to throw a ball v mph in order to reach

How fast do you have to throw a ball (v [mph]) in order to reach a 4^th story window which is 36 ft up?

ball will be thrown with minimum speed such that it just reaches to window (that means it stops ar 36 ft)

so suppose initial speed = u , final velocity v = 0

and a = -9.81 m/s^2 and r = 36 ft = 0.3048 x 36 m

using v^2 - u^2 = 2ar

0 - u^2 = 2 x (-9.81) x (0.3048 x 36)

u = 14.67 m/s = 14.67 x (1/1609)mile / (1./3600 )hr = 32.83 mph