626 Sample size requirements How large a sample is needed to
Solution
a)
Note that
n = z(alpha/2)^2 p (1 - p) / E^2
where
alpha/2 = 0.025
Using a table/technology,
z(alpha/2) = 1.959963985
Also,
E = 0.01
p = 0.03
Thus,
n = 1117.864517
Rounding up,
n = 1118 [ANSWER]
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b)
Note that
n = z(alpha/2)^2 p (1 - p) / E^2
where
alpha/2 = 0.05
Using a table/technology,
z(alpha/2) = 1.644853627
Also,
E = 0.01
p = 0.03
Thus,
n = 787.3131451
Rounding up,
n = 788 [answer]
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As we can see, decreasing the level of confidence made the minimum sample size decrease as well. [ANSWER]

