However Im also trying to get the program to look like this

However, I\'m also trying to get the program to look like this when the user inputs a word:

I just can\'t seem to get the spacing right in this program... Here\'s my code:

import java.util.Scanner;

import java.io.*;

public class PA11 {

   /**
   * Program execution point:
   * input text via console input,
   * output counts for each letter
   * found in the input (case-insensitive)
   *
   * @param args command-line arguments (ignored)
   */

/**The java program that promps user to enter a text string
* on console.When enter text is complete, press enter and
* press cntl+z (on windows) to stop reading.
* Then prints the count of each small and capital letter
* count on console*/
   public static void main(String args[])

   {

   Scanner input=new Scanner(System.in);

   String input1=new String(\"\");//input string

   String temp;//to read strings line by line

   char[] c=new char[26];//to store string in characters format

   int[] a=new int[26];//to count Number of Characters

   char ch,temp1;
     
System.out.print(\"Enter text: \");  

   {
   while(input.hasNext()){
   temp=input.nextLine();//used to read string

   input1=input1.concat(temp);//appending temp string to main string
   }

   c=input1.toCharArray();//converting string to char[]
  

   for(int i=0;i<c.length;i++){
         
   if(Character.isLetter(c[i]))//to check letter is Character or not

   {

   if(Character.isLowerCase(c[i]))

   c[i]=Character.toUpperCase(c[i]);

   int index=c[i]-\'A\';//finding index

   int b=a[index];

   b++;

   a[index]=b;//incrementing value in an array

   }

   }
   for(int i=0;i<a.length;i++)

   {
         
       if(a[i] > 0){

   System.out.printf((\"%c: \") + (\"%d\ \"), i + 65 , a[i]);      
}

   }
   }
   }
}

Any help would be greatly appreciated! Thanks.

xpected Actual 1Enter text: 1 Enter text

Solution

The below code i wrote for replacing your problem,

The logic what you posted have a extra space inside the statement is the spacing error

\"System.out.println(\"Enter Text: \") , The extra space is delimited after the word \"Text\" is experiencing your problem.

So, try the below program to get the fix solved. By simply execute as java application

Input :

Enter the String: College

Output:

C:1

O:1

L:2

E:2

G:1

import java.util.Iterator;
import java.util.LinkedHashMap;
import java.util.Map.Entry;
import java.util.Scanner;
import java.util.Set;

public class Lines {

   public static void main(String[] args) {
      
       String inputData;
       //Reading String Using Scanner
       Scanner scanner = new Scanner(System.in);
       System.out.print(\"Enter the String:\ \");
       inputData = scanner.nextLine();
       //LinkedHashMap is used to store each character as key and count as a Value in the
       //order in which the characters are placed in the string
       LinkedHashMap<Character, Integer> hashMap = new LinkedHashMap<Character, Integer>();
      
       int i=0;
       while(inputData.length() > i) {
           char ch = Character.toUpperCase(inputData.charAt(i));
           if(hashMap.containsKey(ch)){ // checking whether character containing in the Map
               hashMap.put(ch,hashMap.get(ch)+1); // if there added the 1+count to original count in the Map value
           }
           else {
               hashMap.put(ch, 1); // stores each character in the Map with <Key,Value> as <Character,Integer>
           }
           i++;
       }
      
       Set<Entry<Character, Integer>> set = hashMap.entrySet(); // Storing entries into Set
       Iterator<Entry<Character, Integer>> itr = set.iterator(); // Iterating the keys using Iterator

       while(itr.hasNext()){
           Entry<Character, Integer> entry = itr.next();
           System.out.println(entry.getKey()+\":\"+entry.getValue()); // printing the values as key and value
       }
   }

}