Consider the following code that runs on a system with a 64K

Consider the following code that runs on a system with a 64KB set associative cache. int array[4096];//int is 4 bytes for (int i = 0; i

Solution

The maximum number of array blocks that are stored in the cache at any point in time for the address breakdown is 128.

The array blocks are divided into 32*4.So the maximum number blocks taken is 128.

Each bit have 8 blocks.But here that was not an octet .

So we have to arrange the pattern. Then it will become 4 blocks of the bit.

128-bit computing is very unlikely at processor level.

128-bit virtual addresses may occur for memory mapping over very large storage spaces fo mapping storage volumes on top of a very large filesystem capable of storing a single file.

A CPU cache is a hardware cache used by the centrak processing unit of a computer to reduce the average cost to access data from the ,ain memory .

The cache is a smaller , faster memory which stores copies of the data from frequently used main memory locations.

Most cpu\'s have different caches, including instruction and data caches, where the data cache is usually organized as a hierarchy of more cache levels.

The original processor had a four-set associative data cache of 8kb in size., with 64-byte cache blocks.

Hence, there are 8/64=128 cache blocks.

The number of sets is equal to the number of cache blocks divided by the number of ways of associativity , leads to 128/4=32 sets, and 32 different indices.

There are 64 possible offsets since the CPU address is 32 bits, implies 21+5+6=32 and hence 21 bits for the tag field.

The original processor had a 8-way associative with 128-byte cache blocks..