1 Vde 0 Vab bc 2 1 V Explanation SolutionAns Given circuit i

1. Vde 0 Vab bc 2 1 V Explanation:

Solution

Ans)

Given circuit is open means its end terminals are not connected left open,so resistance will be infinity

As per ohm\'s law I=V/R

In this circuit R=R+infinity=infinity

so I₁=V/infinity=0 A

I₁=0 A so there is no current in the circuit infact it is 0A

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Vab=I₁*R=0*R=0 V again from ohm\'s law

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Between points b and c it is conducting wire assumed to be zero resistance 0 ohms ,so

Vbc=I₁*0=0*0=0 V

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Using KVL --kirchoff\'s voltage law

Vce=V-Vab-Vbc-Ved=1-0-0-0=1 V

Vce=1 V

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Vde is similar to Vbc Vde=I1*0=0 V as between e and d pure conductor with resistance 0 ohms

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Vad is just across volatge source V so Vad=V =1 V

Vad=1 V

This value is incorrectly marked as 0 in your answer