The allowed energies of a simple atom are 000 eV 433 eV and

The allowed energies of a simple atom are 0.00 eV, 4.33 eV, and 5.48 eV. What wavelengths appear in the atom\'s emission spectrum? Enter your answers in ascending order separated by commas. What wavelengths appear in the atom\'s absorption spectrum? Enter your answers in ascending order separated by commas.

Solution

1. energy for state n = 1 is 0.00 eV

energy for state n = 2 is 4.33 eV

energy for state n = 3 is 5.48 eV

Allowed emission will be

A. from n = 3 to 2 and for this spectrum wavelength will be

E = hc/lambda

lambda = hc/E = 6.634*10^-34*3*10^8/(1.15*1.6*10^-19) = 1081.63 nm

B. from n = 3 to 1 and for this spectrum wavelength will be

E = hc/lambda

lambda = hc/E = 6.634*10^-34*3*10^8/(5.48*1.6*10^-19) = 226.98 nm

A. from n = 2 to 1 and for this spectrum wavelength will be

E = hc/lambda

lambda = hc/E = 6.634*10^-34*3*10^8/(4.33*1.6*10^-19) = 287.26 nm

2. Answer will be same for absorption spectrum

1081.63 nm, 226.98 nm, and 287.26 nm

Let me know if you have any doubt.