Use the Superposition theorem to find V0 in the circuit Solu
Solution
By using superposition theorem first we will make
Current source active
Voltage source make it zero i.e short
Now find Vo due to current source Vo(current)
as 2k and 1k in series equvalent resistance Req=2+1=3k, now 3k is in parallel with 6k as voltage source is shorted
Total resistance =Rt= Req parllel 6k=Req*6k/(Req+6k)=18/9=2k
Vo(current)=I*Rt=2m *2k=4 V
Now make
Voltage source active
current source make it zero i.e open
Now 6k and 2k and 1 k in series Rt=6k+1k+2k=9k
Vo(voltage)=V*6K/9k (voltage division) 3*6/9= 2V
Vo(voltage)=2 V
By superposition theorem Vo=Vo(voltage)+Vo(current)=2+4=6 V
so Vo=6 V
