R programmingSolution Binomial NOrmal a PX136 1 c 02622 PZ

R programming

Solution

                 Binomial                 NOrmal

a) P(X<7) = 0.6098                    Mean = 9, std dev = 0.126

                                               P(z<-1.59) = 0.0559

b) 0.7448                                  P(Z>-1/0.0730) = P(Z>-13.6) = 1

c) 0.2622                                  P(Z<=-2.5/0.1369) = P(Z<-1,826) = 0.0336

d) 2.963x10^-10                           P(Z>50-20/0.0212)=2358 =0.00

Note that as no of trials increases this approximaion gives a reliable result.