Determine the equivalent spring constant for the system show
Solution
>> For Parallel Combination of Two Springs,
Ax, Displacement is same.
So, x1 = x2 =x
As, Net Force, F = F1 + F2
=> K*x = K1*x1 + K2*x2
=> K = k1 +k2 , i.e,
Equivalent Spring Constant is Summation of all....
>> In Series System,
As, Force is same in each spring,
=> F = F1 = F2
and, x = x1 + x2 [ Because net Displacement = Sum of individual spring displacements ]
=> F/K = F1/K1 + F2/K2
=> 1/K = 1/K1 + 1/K2 , i.e,
Reciprocal of Equivalent Spring Constant is sum of reciprocalof individual spring constants
>> Now, in our system, k1 & k2 are in parallel
So Let, K\" = Equivalent of these two
=> K\" = k1 + k2
>> Now, This K\" & k3 are in Series.
Let, K = Equivalent Spring Constant of the whole system
So,
1/K = 1/K\" + 1/k3
=> K = (K\")(k3)/[K\" + k3]
=> K = (k1 + k2)*(k3)/[k1 + k2 + k3] .......ANSWER........
