Refer to the figure below Let the mass of the block be 87 kg

Refer to the figure below. Let the mass of the block be 8.7 kg and the angle theta be 30degree. (a) Find the tension in the cord. N (b) Find the normal force acting on the block. N (c) If the cord is cut, find the magnitude of the resulting acceleration of the block. m/s^2

Solution

a_x = 0, T - F_gx = 0

T = F_gx = m g sin 30 = 8.7 * 9.8 * sin 30

T = 42.63 N

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a_y = 0, N - F_gy = 0

N = F_gy = m g cos 30 = 8.7 * 9.8 * cos 30

T = 73.84 N

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T = 0, F_gx = m a

42.63 = 8.7 a

a = 4.9 m/s²