how to solve for cosh with polar coordinates Step by Step 3

how to solve for cosh with polar coordinates? Step by Step

3 phase 60 Hz Transimission Line under consideration length of the line (L) = 250 mile voltage at the sending end Vs = 220 kv line parameters are: R = 0.2 ohm/mile X = 0.8 ohm/mile Y = 5.3 mus/mile To find: sending end current when there is no load. =220/squareroot3 Lodegree volts z = R + jX = 0.2 + j0.8 ohm/mile y = j5.3 times 10^-6 s/mile Z_e = squarerootz/y = squareroot0.2 + j0.8/j5.3 times 10^-6 = 394.448 -7.02degree ohm Also, gamma = squarerootzy = squareroot(0.2+j0.8)(5.3 times 10^-6 90degree) = 0.002 82.982 degree mile^-1 Now, v_s = v_R cos h(rL) + I_R Z_c sin h(rl) and I_s = I_R cos h(rL) + v_R/Z_c sin h(rl) Since here no load condition to given I_R = 0 From (1) V_R_NL = V_s/cos h(rL) = 220/squareroot 0degree/cos h (rL) = 145766 - j5307 vol5

Solution

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