Suppose that E and F are two events and that PE 04 and PFE
Solution
P(F/E) =0.6 and
P(E) =0.4
P(F/E) = P(F and E)/P(E)
Substitute and get
0.6 = P(F and E)/0.4
P(F and E)= 0.6(0.4) = 0.24

P(F/E) =0.6 and
P(E) =0.4
P(F/E) = P(F and E)/P(E)
Substitute and get
0.6 = P(F and E)/0.4
P(F and E)= 0.6(0.4) = 0.24
