Find AB if BC 3 BD 5 and AD 3 AB SolutionIn triangle BDC
Find AB if BC = 3, BD = 5, and AD = 3. AB =
Solution
In triangle BDC
BD2=CD2+BC2
52=CD2+32
CD2=16
CD=4
IN triangle BCA
AB2=BC2+ AC2
AB2= 32+(3+4)2
AB2=9 +49
AB=sqrt 58

In triangle BDC
BD2=CD2+BC2
52=CD2+32
CD2=16
CD=4
IN triangle BCA
AB2=BC2+ AC2
AB2= 32+(3+4)2
AB2=9 +49
AB=sqrt 58
