for the function yx43x26x1 find the tangent line through the

for the function y=x^4-3x^2+6x+1 find the tangent line through the point (1,5)

y\'(x) = 4x³-6x +6

we know, slope of line at x= 1 is :

y\'(1) = 4 -6 +6 = 4

Now, it passes from (1,5)

So, equation is :

y-5 = 4(x-1)

or,

y -4x -1 =0

$for the function y=x^4-3x^2+6x+1 find the tangent line through the point (1,5)Solutiony\'(x) = 4x3-6x +6 we know, slope of line at x= 1 is : y\'(1) = 4 -6 +6 =$

for the function yx43x26x1 find the tangent line through the

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