An apparatus like the one shown is constructed so that L 80
An apparatus like the one shown is constructed so that L = 80 cm. C02 [gas 1] is placed in the lower tube [A] and air [gas 2] in the upper tube [B]. Both gases are at standard atmospheric pressure and 25 deg-C. The data obtained after 2 hrs of diffusion is: time (hrs) X1A X1B 2 0.55 0.45 Calculate the value of D12.
Solution
D12 = X1A - X1B / 2*L*t ( L = 80 cm t = 2 * 60 * 60 sec )
= (0.55 - 0.45) / ( 2 * 0.8 * 2 * 60 * 60)
= 8.68 * 10^-6
![An apparatus like the one shown is constructed so that L = 80 cm. C02 [gas 1] is placed in the lower tube [A] and air [gas 2] in the upper tube [B]. Both gases An apparatus like the one shown is constructed so that L = 80 cm. C02 [gas 1] is placed in the lower tube [A] and air [gas 2] in the upper tube [B]. Both gases](/WebImages/24/an-apparatus-like-the-one-shown-is-constructed-so-that-l-80-1061576-1761554652-0.webp)