An apparatus like the one shown is constructed so that L 80

An apparatus like the one shown is constructed so that L = 80 cm. C02 [gas 1] is placed in the lower tube [A] and air [gas 2] in the upper tube [B]. Both gases are at standard atmospheric pressure and 25 deg-C. The data obtained after 2 hrs of diffusion is: time (hrs) X1A X1B 2 0.55 0.45 Calculate the value of D12.

Solution

D12 = X1A - X1B / 2*L*t    ( L = 80 cm t = 2 * 60 * 60 sec )

        = (0.55 - 0.45) / ( 2 * 0.8 * 2 * 60 * 60)

        = 8.68 * 10^-6

 An apparatus like the one shown is constructed so that L = 80 cm. C02 [gas 1] is placed in the lower tube [A] and air [gas 2] in the upper tube [B]. Both gases

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