2413 Begin Date 1232016 120000 AM 21620168 0000 Due AMEMumat

24.1-3 Begin Date: 1/23/2016 12:00:00 AM 2/16/20168 0000 Due AMEMumate (13%) Problem 6: A far sighted person has a near point of 100 cm. 50% Part (a) How far in cm in front or behind the retina does the image of a object placed 25 cm from the eye form? Use the cornea to retina distance of 25 cm. Grade Summary 96% sino l coso tano ID 7 8 9 Attempts remaining: 4 cotan0 asino acoso 4 5 6 per attempt) detailed view 1 2 3 atan0 acotano sinh0 cosho tanho cotanho ODegrees Radians I give up! Hints: 0 for a 0% deduction. Hints remaining 0 Feedback: 1% deduction per feedback. 50% Part (b) In front or behind the retina? All content c 2016 Expen TA,LLC

Solution

a)

Using the relation,

1/v + 1/u = 1/f

So, 1/2.5 + 1/100 = 1/f

So, f = 2.44 cm

So, For the object to be located at u = 25 cm

So, 1/25 + 1/v = 1/2.44

So, v = 2.704 cm

So, the image is formed (2.704 - 2.5 = 0.204 cm) behind the cornea <-------answer

b)

It is behind the retina (as v > 2.5 cm)