Let fz be the complex function defined by where z is the con

Let f(z) be the complex function defined by where z is the conjugate of z. Find the limit of f(z) - f(0) / z - 0 when z goes to 0 along the real line, and along the imaginary line. Deduce whether f(z) is differentiable at z_0 = 0 The limit of f(z) - f(0) / z - 0 when z goes to 0 along the real line is The limit of f(z) - f(0) / z - 0 when z goes to 0 along the imaginary line is Hence f(z) is differentiable at z_0 = 0

Solution

its true