Consider AaBbDdeeGg times aaBbDDeeGg If loci are on separate

Consider AaBbDdeeGg times aaBbDDeeGg If loci are on separate chromosomes, how many chromosome pairs are involved? How many different types of gametes can each individual produce? How many different genotypes if offspring? How many different phenotypes in offspring? What fraction of offspring will be aabbddeegg? If A and B loci are linked, how do the answers change?

Solution

a) 5pairs of chromosomes

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b) Number of gametes =2^n

n= heterozygous loci

Parent 1--------Aa    Bb Dd ee Gg

N=4   Number of gametes =2^4 =16

Parent 2--------aa    Bb DD ee Gg

N=2   Number of gametes =2^2 =4

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Phenotypes : 8

There are 8 distinct phenotypes

aabbdDeege: 288
aabbdDeege: 288
aabbdDeege: 96
aabbdDeege: 96
aabbdDeege: 96
aabbdDeege: 96
aabbdDeege: 32

aabbdDeege: 32

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fraction =       aabbdDeege:           32 /

32=1024=0.03125-answer

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There are 48 distinct genotypes

AaBBDDeeGG: 1.6 %
AaBBDDeegG: 1.6 %
AaBBdDeeGG: 1.6 %
AabBDDeeGG: 3.1 %
AaBBdDeegG: 1.6 %
AabBDDeegG: 3.1 %
AabBdDeeGG: 3.1 %
AabBdDeegG: 3.1 %
aaBBDDeeGG: 1.6 %
aaBBDDeegG: 1.6 %
aaBBdDeeGG: 1.6 %
aabBDDeeGG: 3.1 %
aaBBdDeegG: 1.6 %
aabBDDeegG: 3.1 %
aabBdDeeGG: 3.1 %
aabBdDeegG: 3.1 %
AaBBDDeeGe: 1.6 %
AaBBDDeege: 1.6 %
AaBBdDeeGe: 1.6 %
AabBDDeeGe: 3.1 %
AaBBdDeege: 1.6 %
AabBDDeege: 3.1 %
AabBdDeeGe: 3.1 %
AabBdDeege: 3.1 %
aaBBDDeeGe: 1.6 %
aaBBDDeege: 1.6 %
aaBBdDeeGe: 1.6 %
aabBDDeeGe: 3.1 %
aaBBdDeege: 1.6 %
aabBDDeege: 3.1 %
aabBdDeeGe: 3.1 %
aabBdDeege: 3.1 %
AabbDDeeGG: 1.6 %
AabbDDeegG: 1.6 %
AabbdDeeGG: 1.6 %
AabbdDeegG: 1.6 %
aabbDDeeGG: 1.6 %
aabbDDeegG: 1.6 %
aabbdDeeGG: 1.6 %
aabbdDeegG: 1.6 %
AabbDDeeGe: 1.6 %
AabbDDeege: 1.6 %
AabbdDeeGe: 1.6 %
AabbdDeege: 1.6 %
aabbDDeeGe: 1.6 %
aabbDDeege: 1.6 %
aabbdDeeGe: 1.6 %
aabbdDeege: 1.6 %

There are 8 distinct phenotypes