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Solution
Formulating the null and alternative hypotheses,
Ho: u <= 25
Ha: u > 25
As we can see, this is a right tailed test.
Thus, getting the critical t,
df = n - 1 = 4
tcrit = + 2.131846786
Getting the test statistic, as
X = sample mean = 27.54
uo = hypothesized mean = 25
n = sample size = 5
s = standard deviation = 5.470648956
Thus, t = (X - uo) * sqrt(n) / s = 1.038197243
Also, the p value is
p = 0.178906737
As |t| < 2.1318, and P > 0.05, we FAIL TO REJECT THE NULL HYPOTHESIS.
Thus, there is no sufficient evidence at 0.05 level that the population mean MAWL exceeds 25. [CONCLUSION]
