A pomegranate is thrown from ground level straight up into t

A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 192 feet per second. Its height in feet at t seconds is f(t)=?16t2+192t. Find the time it reaches its highest point and the maximum height.

Reaches highest point when t= (include units)
Maximum height = . (include units)

Solution

Differentiate to get maxima. It is at t = 6seconds. Hence height = 1204ft
A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 192 feet per second. Its height in feet at t seconds is f(t)=?16t2+

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