Evaluate the integral by making the substitution Solutionu

Evaluate the integral

$\"\\int$

by making the substitution $\"u$ .

$\"+\\,C\"$

u = x^4 - 8

du = 4x^3 dx

x^3 dx = du/4

Therefore:

int x^3 (x^4-8)^9 dx =

int u^9 /4 du =

1/40 u^10 + C =

1/40 (x^4 - 8)^10 + C

Evaluate the integral by making the substitution. Solutionu = x^4 - 8 du = 4x^3 dx x^3 dx = du/4 Therefore: int x^3 (x^4-8)^9 dx = int u^9 /4 du = 1/40 u^10 +

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