Solve x4 x2 2x 3 0 by a Fixedpoint method and b Newtons
     Solve x^4 - x^2 + 2x - 3 = 0, by a) Fixed-point method, and b) Newton\'s method by staring from x_0 = 1. For each method, do 5 steps of iteration and keep 5 decimal places in each iteration.  Or  You can also do the iterations in Excel, where the iteration can stop when |x_n+1 - x_n|     
 
  
  Solution
Using fixed point method, we don\'t get a solution. It keeps jumping between the two values, neither of which are an answer of the equation
Using newton\'s method:
Iterations
Using newton\'s method we get the answer as 1.1944
| xi | xi+1 | 
| 1 | 1.5 | 
| 1.5 | 0.774194 | 
| 0.774194 | 1.775317 | 
| 1.775317 | 0.515461 | 
| 0.515461 | 1.850142 | 
| 1.850142 | 0.462753 | 
| 0.462753 | 1.833359 | 
| 1.833359 | 0.474014 | 
| 0.474014 | 1.837681 | 
| 1.837681 | 0.471083 | 
| 0.471083 | 1.836593 | 
| 1.836593 | 0.471819 | 
| 0.471819 | 1.836869 | 
| 1.836869 | 0.471632 | 
| 0.471632 | 1.836799 | 
| 1.836799 | 0.47168 | 
| 0.47168 | 1.836817 | 
| 1.836817 | 0.471668 | 
| 0.471668 | 1.836812 | 
| 1.836812 | 0.471671 | 
| 0.471671 | 1.836813 | 
| 1.836813 | 0.47167 | 

