Given that z is a standard normal random variable compute th

Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals).

***The answer is NOT .1799 as previously provided by rapunzal so I need correct answer please. Thanks.

Solution

z1 = lower z score =    0.52      
z2 = upper z score =     1.22      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.698468212      
P(z < z2) =    0.888767563      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.1903     [ANSWER]

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