Develop a SIMPLE program in C that first asks the user to in

Develop a SIMPLE program in C++:

that first asks the user to input a signed number, for example 48, then converts it to binary number by using Two’s Complement regulations. Do the same for the second inputted number, e.g., -17. Then compute the summation of these two numbers, output the results in binary format first, then if there is an overflow, display error message; otherwise, convert the result to decimal value and show it on the screen, e.g., 48 + (-17) = 31.

Note

that there is no limit to the number of bits the program can handle. For convenience, the program can assume it is for eight-bit binary numbers. Also assume all inputs are valid. CANNOT use library functions in the header file to implement it.

Solution

#include <iostream>
#include <string>
#include <cmath>

using namespace std;

string DecimalToBinary(unsigned int dec){
    char binary[33] = {0};

    int ix = 32; // subscript of current character
    do{
        binary[--ix] = \'0\' + dec % 2;
        dec /= 2;
    } while (dec);

    return (binary+ix);    // ix is offset into char array where answer begins
}

int convertBinaryToDecimal(int* n){
    int decimalNumber = 0, i = 32, j=0, remainder;
    while (i>0){
        remainder = n[i];
        decimalNumber += remainder*pow(2,j);
        ++j;
        --i;
    }
    return decimalNumber;
}

int* add(string num1, string num2, int* sum){
    int a[32];
    int b[32];
    int result[32];//, sum[32];
    int carry = 0;
    for (int k=0; k<32; k++){
        a[k] = (int)num1[k];
        b[k] = (int)num2[k];
    }

    for(int i=0; i<4; i++){
        if(a[i]+b[i]+carry==3){
            result[i]=1;
            carry=1;
        }
        if(a[i]+b[i]+carry==2){
            result[i]=0;
            carry=1;
        }
        if(a[i]+b[i]+carry==1){
            result[i]=1;
            carry=0;
        }
        if(a[i]+b[i]+carry==0){
            result[i]=0;
            carry=0;
        }
    }
    result[32]=carry;
    for(int j=32; j>=0; j--){
        sum[32-j]<<result[j];
    }

}

int main(){
    int decimal;
    int num1, num2;
    string a, b;
    int c[32];
    cout << \"Enter decimal Number: \";
    cin >> num1;
    cout << \"\ Enter another decimal Number: \";
    cin >> num2;
    a = DecimalToBinary(num1);
    b = DecimalToBinary(num2);
    add(a, b, c);
    cout<<convertBinaryToDecimal(c);
    return 0;
}