Question 1 5 pts Skip to question text A chisquare test for

Question 1 5 pts Skip to question text. A chi-square test for goodness-of-fit is used to test whether or not there are any preferences among 3 brands of peas. If the study uses a sample of n = 60 subjects, then the expected frequency for each category would be: 60 20 33 30 Flag this Question Question 2 5 pts Skip to question text. When the variables of interest are both categorical and the decision maker is interested in determining whether a relationship exists between the two, a statistical technique known as contingency analysis is useful. True False Flag this Question Question 3 5 pts Skip to question text. A survey was recently conducted in which males and females were asked whether they owned a laptop personal computer. The following data were observed: Males Females Have Laptop 120 70 No Laptop 50 60 Given this information, if an alpha level of .05 is used, the test statistic for determining whether having a laptop is independent of gender is approximately 14.23. True False Flag this Question Question 4 5 pts In conducting a test of independence for a contingency table that has 4 rows and 3 columns, the number of degrees of freedom is 11. True False Flag this Question Question 5 5 pts Skip to question text. If a contingency analysis test is performed with a 4 × 6 design, and if alpha = .05, the critical value from the chi-square distribution is 24.9958 True False Flag this Question Question 6 5 pts Skip to question text. A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collected the following data based on a random sample of 100 days. Frequency Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100 Assuming that a goodness-of-fit test is to be conducted using a 0.10 level of significance, the critical value is: 7.7794 9.4877 11.0705 9.2363 Flag this Question Question 7 5 pts Skip to question text. A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collected the following data based on a random sample of 100 days. Frequency Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100 To conduct a goodness-of-fit test, what is the expected value for Friday? 20 25 100 16 Flag this Question Question 8 5 pts Skip to question text. A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collected the following data based on a random sample of 100 days. Frequency Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100 Based on these data, conduct a goodness-of-fit test using a 0.10 level of significance. Which conclusion is correct? Arrivals are uniformly distributed over the weekday because (test statistic) > (critical value). Arrives are uniformly distributed over the weekday because (test statistic) < (critical value). Arrivals are not uniformly distributed over the weekday because (test statistic) > (critical value). Arrivals are not uniformly distributed over the weekday because (test statistic) > (critical value). Flag this Question Question 9 5 pts Skip to question text. We are interested in determining whether the opinions of the individuals on gun control (as to Yes, No, and No Opinion) are uniformly distributed. A sample of 150 was taken and the following data were obtained. Do you support gun control Number of Responses Yes 40 No 60 No Opinion 50 The conclusion of the test with alpha = 0.05 is that the views of people on gun control are: inconclusive. uniformly distributed. not uniformly distributed. None of the above Flag this Question Question 10 5 pts The goodness-of-fit test is always a one-tail test with the rejection region in the upper tail. True False Flag this Question Question 11 5 pts Skip to question text. A survey was recently conducted in which males and females were asked whether they owned a laptop personal computer. The following data were observed: Males Females Have Laptop 120 70 No Laptop 50 60 Given this information, if having a laptop is independent of gender, the expected number of males with laptops in this survey is 150. True False Flag this Question Question 12 5 pts Skip to question text. The logic behind the chi-square goodness-of-fit test is based on determining how far the actual observed frequencies are from the expected frequencies. True False Flag this Question Question 13 5 pts Skip to question text. The Conrad Real Estate Company recently conducted a statistical test to determine whether the number of days that homes are on the market prior to selling is normally distributed with a mean equal to 50 days and a standard deviation equal to 10 days. The sample of 200 homes was divided into 8 groups to form a grouped data frequency distribution. The degrees of freedom for the test will be 7. True False Flag this Question Question 14 5 pts Skip to question text. Consider a goodness-of-fit test with a computed value of chi-square = 1.273 and a critical value = 13.388, the appropriate conclusion would be to: reject H0. take a larger sample. take a smaller sample. fail to reject H0. Flag this Question Question 15 5 pts Skip to question text. A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collected the following data based on a random sample of 100 days. Frequency Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100 What is the value of the test statistic needed to conduct a goodness-of-fit test? 7.7794 2.46 8.75 2.50 Flag this Question Question 16 5 pts Skip to question text. A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collected the following data based on a random sample of 100 days. Frequency Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100 Based on this information how many degrees for freedom are involved in this goodness of fit test? 4 99 100 5 Flag this Question Question 17 5 pts Skip to question text. If the test statistic for a chi-square goodness-of-fit test is larger than the critical value, the null hypothesis should be rejected. True False Flag this Question Question 18 5 pts Skip to question text. A survey was recently conducted in which males and females were asked whether they owned a laptop personal computer. The following data were observed: Males Females Have Laptop 120 70 No Laptop 50 60 Given this information, if an alpha level of .05 is used, the critical value for testing whether the two variables are independent is x2 = 3.8415. True False Flag this Question Question 19 5 pts Skip to question text. A researcher is using a chi-square test to determine whether there are any preferences among 4 brands of orange juice. With alpha = 0.05 and n = 30, the critical region for the hypothesis test would have a boundary of: 8.17 7.81 42.25 8.71 Flag this Question Question 20 5 pts Skip to question text. A survey was recently conducted in which males and females were asked whether they owned a laptop personal computer. The following data were observed: Males Females Have Laptop 120 70 No Laptop 50 60 Given this information, if an alpha level of .05 is used, the sum of the expected cell frequencies will be equal to the sum of the observed cell frequencies. True False

Solution

Q1.
the expected frequency for each category would be = 60/3 = 20

Q2.
True

Q3.
False , it is 8.8912

Q4.
False, ^2 degrees of freedom = ( r-1 ) * (c-1) = 3 * 2 = 6

Q5.
True, ^2 degrees of freedom = ( r-1 ) * (c-1) = 3 * 5 = 15, tabular value is 24.9958