Let X denote a random variable taking the values 0 and 1 wit
Let X denote a random variable taking the values 0 and 1, with Pr[X = 0] = 1/4 and Pr[X = 1] = 3/4. Let Y = 1 - 2X. What is E(X)? Using the rules for expectations, what is E(Y)? What is E(Y|X = 1)? What is E(Y|X = 0)? Use the law of iterated expectations to calculate E(Y). Does you answer agree with your answer to part (a) above? What is Var(E(Y))? What is What is Var(E(Y|X))? What is Var(E(Y|X = 1))? What is Var(E(Y|X)|X)?
Solution
The pdf of X is as follows:
E(Y) = E(1-2x)
= 1-2E(X) = 1-3/2 = -1/2
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b) E(Y/x=1) = E(y=-1) = 3/4(-1) = -3/4
E(Y/x=0) = E(y=1) = 1/4(1) = 1/4
E(Y) = -3/4 +1/4 = -1/2
yes both are the same
c) Var (Y) = Var(1-2x)
= 4 var(x) = 3
d) Var (Y/x=1) = -1(3/4) = -3/4
Var(Y/x=0) = 1(1/4) = 1/4
Var(Y/x) = -1/2
| x | 0 | 1 | Total |
| p | 1/4 | 3/4 | 1 |
| px | 0 | 3/4 | 3/4 |
| px^2 | 0 | 3/4 | 3/4 |
| Mean | 3/4 | ||
| Var(x) | 3/4 |
![Let X denote a random variable taking the values 0 and 1, with Pr[X = 0] = 1/4 and Pr[X = 1] = 3/4. Let Y = 1 - 2X. What is E(X)? Using the rules for expectati Let X denote a random variable taking the values 0 and 1, with Pr[X = 0] = 1/4 and Pr[X = 1] = 3/4. Let Y = 1 - 2X. What is E(X)? Using the rules for expectati](/WebImages/25/let-x-denote-a-random-variable-taking-the-values-0-and-1-wit-1062573-1761555318-0.webp)