Rewrite the expression 4 log x 3 logx2 1 2 logx 1 as a s

Rewrite the expression 4 log x - 3 log(x^2 + 1) + 2 log(x - 1) as a single logarithm log A. Then the function You have attempted this problem 1 time. Your overall recorded score is 0%. You have unlimited attempts remaining.

Solution

4logx -3log(x^2 +1) +2log(x-1)

use the properties : logx^a = alogx

logA - logB = log (A/B)

4logx -3log(x^2 +1) +2log(x-1) = logx^4 - log(x^2 +1)^2 +log(x-1)^2

= log(x^4(x -1)^2/(x^2+1)^3 )