I got lost trying to figure this out Find the halflife of a

I got lost trying to figure this out

Find the half-life of a radioactive substance that decays by 8% in 6 years. ()

We have to use the formula

A=A₀2^-(t/h)

Here A₀= initial value

A= value at time t

h= half life

Let initial amount,A₀=1

Therefore amount at time t=6 yrs is .92

.92=1 * 2^-(6/h)

taking log on both sides

log .92= (-6/h)log 2

log .92/log 2=-6/h

h=-6 log2/log.92

h= 49.9 yrs

Therefore the half life is 49.9 yrs