In 2000 the deer population in a certain area was 800 The nu

In 2000, the deer population in a certain area was 800. The number of deer increases exponentially at a rate of 7% per year. Predict the population in 2009. N = N_oe^kt Find the balance in an account at the end of 8 years if $6000 is invested at an interest rate of 12% compounded continuously. A = Pe^rt

Solution

N = No e^kt

initial population = 800

rate of increase = 7%

plugging the values in the formula

N = 800 e^ (.07*9) = 1502.08

population in 2009 = 1502 approximately

27) A = Pe^rt

time = 8 years

P = $ 6000

rate of interest = 12% = .12

plugging the values in the formula

A = 6000* e ^(.12*8) = 15670.178

therefore, balance in account after 8 years = $ 15670.178