p 213 u E 103 SolutionP136 u is the square of a std normal v

Solution

P(1.36

u is the square of a std normal variate

Hence if Z is the std normal variate

then 1.36

-1.17

Prob for (-1.17

=0.3790+0.4989

= 0.8779

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2) u lies between 2.3 and 10,3

Hence z lies between -1.52 and 3.21

Prob = 0.4357+0.4987

= 0.9344