A heterozygous right handed and homozygous blue eyed man mar

A heterozygous right handed and homozygous blue eyed man married a heterozygous right handed and heterozygous brown eyed woman. Assume that right handedness is dominant \"R\" and brown eyes are also dominant \"B\". The probabilities for their offspring would include:

8:8 brown eyes and right handed
        4:8 brown eyes and right handed
        1:8 blue eyes and left handed
        3:8 blue eyes and right handed
        1:8 brown eyes and left handed

more than one may be correct

Solution

3:8 blue eyes and right handed;

1:8 brown eyes and left handed;

1:8 blue eyes and left handed

Assume that the gene coding for right-handedness is R and the gene coding for left handedness is r; R is dominant over r. Similarly, assume that the gene coding for brown eyes is B and the gene coding for blue eyes is b; B is dominant over b.

Cross between a heterozygous right handed and homozygous blue eyed man (Rr bb) married a heterozygous right handed and heterozygous brown eyed woman (Rr Bb) will have the progeny with the following genotypes:

Rr bb* Rr Bb --> R_B_ (6/16, right handed, brown eyed), R_bb (6/16, right handed, blue eyed), rrBb (2/16, left handed, brown eyed), rrbb (2/16, left handed, blue eyed).