In the equation below f is a frequency and L is a length Wha
In the equation below f is a frequency, and L is a length. What are the dimensions of a?
In the equation below f is a frequency, and L is a length. What are the dimensions of a 1/f = 2.pi.root L/aSolution
On the left hand side:
Dimension of frequency is T-1. So, dimension of 1/f will be T.
Now on the right hand side,
2pi is dimension less constant and L is length
To obtain the dimension of T on the right side, we have to divide the length dimension by another length dimension and multiply by T2.
Hence, dimension of 1/a = T2/L
So, dimensions of a = L/T2 = LT-2
