Homework SourseSolve the given initialvalue problem and give the largest in
Solve the given initial-value problem and give the largest interval I on which the solution is defined
dy/dt + 2(t + 1)y^2 = 0, y(0) = -1/8
Please show wrok.
Thank you
dy/dt + 2(t + 1)y^2 = 0, y(0) = -1/8
Please show wrok.
Thank you
Solution
\\(y\'/y^2 = 2(t+1)\\) Integrating: \\(-1/y = t^2 + t + c\\) Substituting \\(y(0) = -1/8\\) c = 8 \\( f(t) = (t^2 + t + 8)^{-1}\\)
