The total lung capacity of a patient is 55 liters Find the p

The total lung capacity of a patient is 5.5 liters. Find the patient’s inspiratory reserve volume if the patient’s vital capacity was 4.2 liters, the tidal volume was 500 ml, and the expiratory reserve volume was 1.2 liters.

Solution

Answer:

Inspiratory reseve volume (IRV )= VC - (TV + ERV)

VC= Vital capacity

TV= Tidal volume

ERV= Expiratory reseve volume

= 4.2- (0.5 + 1.2)

= 2.5 Liters