Truck tire life is normally distributed with a mean of 62302
Truck tire life is normally distributed with a mean of 62,302 miles and a standard deviation of 4,149 miles. What is the probability that a tire lasts between 54,838 and 66,843 miles?
| 0.8271 | |
| Very likely | |
| 0.8631 | |
| 0.0360 |
Solution
Let X be the nomally distributed variable
Step1:
Find Z-score
Z-score = X -mean/standard deviation
Z1 = 66843 - 62302/4149 = 1.09448
Z2 = 54838 - 62302/4149 = -1.79899
step2:
P(54838< X < 66843) = P(-1.79899 < Z < 1.09448)
= P(Z < 1.09448) - P(Z < -1.79899)
= 0.8631 - 0.036
= 0.8271 .....ans
